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2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

## How many necklaces can you make with 8 beads of colors?

Eight different beads can be arranged in a circular form in (8-1)!= 7! Ways. Since there is no distinction between the clockwise and anticlockwise arrangement, the required number of arrangements is 7!/2=2520.

## How many necklaces can be made with these beads of different Colours?

The correct answer is 2952 .

## How many different bangles can be formed from 8 different colored heads?

How many different bangles can be formed from 8 different colored beads? Answer: 5,040 bangles .

## How many necklaces are in 7 beads?

It would be 7! = 5040 diffrent necklaces.

## How many necklaces of 12 beads each can be made from 18 beads of various colours?

Correct Option: C

First, we can select 12 beads out of 18 beads in ^{18}C_{12} ways. Now, these 12 beads can make a necklace in 11! / 2 ways as clockwise and anti-clockwise arrangements are same. So, required number of ways = [ ^{18}C_{12} . 11! ] / 2!

## How many necklaces can you make with 6 beads of 3 colors?

The first step is easy: the number of ways to colour 6 beads, where each bead can be red, green or blue, is 3^{6} = 729.

## How many ways can 6 beads of different Colours form a necklace?

When the necklace is unclasped and laid out with its ends separated, there are 6! = 720 distinct ways (permutations) to arrange the 6 different beads.

## How many different change can be made using 5 different Coloured beads?

So there can be 12 different arrangements.

## How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is 21.

## How many necklaces can be made by using 10 round beads all of a different colors?

There are 10 beads of distinct colours; say, A, B, C, D, E, F, G, H, I and J. If no restriction is imposed then, there are (10!) = 3628800 ways to put these ten distinctly coloured beads into a necklace.

## How many ways can 6 differently Coloured beads be threaded on a string?

Assuming that the beads are different, the first bead can be picked in 6 ways. Then the second bead can be picked in 5 ways. And the third bead can be picked in 4 ways, etc. Multiplying these together, we get 6*5*4*3*2*1 = 720 ways.

## What are the number of ways in which 10 beads can be arranged to form a necklace 9 !/ 2 9 10 10?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

## How many necklaces can be made using 7 beads of which 5 are identical red beads and 2 are identical blue beads?

= 720/(120*2) = 3. So we can have 3 different necklaces.

## How many different necklaces can be made with two red beads and four blue beads?

Therefore, there are only two possible necklaces: alternate the colors or group the colors together.

## How many arrangements of beads are possible in a bracelet if there are 6 different designs of beads?

Since there are 6! linear arrangements of six distinct beads, the number of distinguishable circular arrangements is 6! 6=5!