Question: How many bracelet with no luck can be formed from 7 different colored beads?

It would be 7! = 5040 diffrent necklaces.

How many bracelets with no lock can be formed from 6 different colored beads?

= 720 distinct ways (permutations) to arrange the 6 different beads.

How many ways 7 different beads can be arranged to form a necklace?

2520. 5040.

How many necklaces can be formed with 8 different Colour beads?

The number of ways in which 8 different beads be strung on a necklace is. 2500. 2520.

How many arrangements of beads are possible in a bracelet if there are 6 different designs of beads?

Since there are 6! linear arrangements of six distinct beads, the number of distinguishable circular arrangements is 6! 6=5!

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How many necklaces can you make with 6 beads of 3 colors?

The first step is easy: the number of ways to colour 6 beads, where each bead can be red, green or blue, is 36 = 729.

How many ways can 5 beads be arranged in a circular bracelet?

Therefore the total number of different ways of arranging 5 beads is 242=12 . Now, we can select 5 beads from 8 different beads in 56 ways. In each way we can arrange them in 12 ways. Therefore the total number of ways in which 5 beads, chosen from 8 different beads be threaded on a circular ring is 672.

What is circular permutation?

Circular permutation is the total number of ways in which n distinct objects can be arranged around a fix circle.

What are the number of ways in which 10 beads can be arranged to form a necklace 9 !/ 2 9 10 10?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is 21.

How many ways can 7 boys seat around circle?

Complete step-by-step answer:

Since in this question we have to arrange persons in a circle and 7 persons have to be arranged in a circle so that every person shall not have the same neighbor. Hence there are 360 ways to do the above arrangement and therefore the correct option is A.

How many different bangles can be formed from 8 different colored heads?

How many different bangles can be formed from 8 different colored beads? Answer: 5,040 bangles .

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How many ways can 6 differently Coloured beads be threaded on a string?

Assuming that the beads are different, the first bead can be picked in 6 ways. Then the second bead can be picked in 5 ways. And the third bead can be picked in 4 ways, etc. Multiplying these together, we get 6*5*4*3*2*1 = 720 ways.

How many necklaces can be made by using 10 round beads all of a different colors?

There are 10 beads of distinct colours; say, A, B, C, D, E, F, G, H, I and J. If no restriction is imposed then, there are (10!) = 3628800 ways to put these ten distinctly coloured beads into a necklace.