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Eight different beads can be arranged in a circular form in (8-1)!= 7! Ways. Since there is no distinction between the clockwise and anticlockwise arrangement, the required number of arrangements is 7!/2=2520.

## How many ways 8 different beads can be arranged to form a necklace?

The number of ways in which 8 different beads be strung on a necklace is. 2500. 2520.

## How many different bangles can be formed from 8 different colored heads?

How many different bangles can be formed from 8 different colored beads? Answer: 5,040 bangles .

## What are the number of ways in which 10 beads can be arranged to form a necklace?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

## How many bracelets with no lock can be formed from 6 different colored beads?

= 720 distinct ways (permutations) to arrange the 6 different beads.

## How many ways can 8 beads of different Colour be strung on a ring?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

## How many ways can 6 differently Coloured beads be threaded on a string?

Assuming that the beads are different, the first bead can be picked in 6 ways. Then the second bead can be picked in 5 ways. And the third bead can be picked in 4 ways, etc. Multiplying these together, we get 6*5*4*3*2*1 = 720 ways.

## How many different bangles are there?

There are two basic types of bangles: a solid cylinder type; and a split, cylindrical spring opening/closing type. The primary distinguishing factor between these is the material used to make the bangles.

## How many necklaces can be made with these beads of different Colours?

The correct answer is 2952 .

## How many necklaces can be made using 7 beads of which 5 are identical red beads and 2 are identical blue beads?

= 720/(120*2) = 3. So we can have 3 different necklaces.

## How many necklaces can be made by using 10 round beads all of a different colors?

There are 10 beads of distinct colours; say, A, B, C, D, E, F, G, H, I and J. If no restriction is imposed then, there are (10!) = 3628800 ways to put these ten distinctly coloured beads into a necklace.

## How many necklaces can be formed with 7 beads?

It would be 7! = 5040 diffrent necklaces.

## How many arrangements of beads are possible in a bracelet if there are 6 different designs of beads?

Since there are 6! linear arrangements of six distinct beads, the number of distinguishable circular arrangements is 6! 6=5!

## How many different way can 4 keys be arranged on a key ring that has no clasp?

Keep one key fixed in any position in the ring. So, the remaining 4 keys can be arranged in 4! = 24 ways.

## How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is 21.