Eight different beads can be arranged in a circular form in (8-1)!= 7! Ways. Since there is no distinction between the clockwise and anticlockwise arrangement, the required number of arrangements is 7!/2=2520.
How many ways 8 different beads can be arranged to form a necklace?
The number of ways in which 8 different beads be strung on a necklace is. 2500. 2520.
How many different bangles can be formed from 8 different colored heads?
How many different bangles can be formed from 8 different colored beads? Answer: 5,040 bangles .
What are the number of ways in which 10 beads can be arranged to form a necklace?
Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.
How many bracelets with no lock can be formed from 6 different colored beads?
= 720 distinct ways (permutations) to arrange the 6 different beads.
How many ways can 8 beads of different Colour be strung on a ring?
2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.
How many ways can 6 differently Coloured beads be threaded on a string?
Assuming that the beads are different, the first bead can be picked in 6 ways. Then the second bead can be picked in 5 ways. And the third bead can be picked in 4 ways, etc. Multiplying these together, we get 6*5*4*3*2*1 = 720 ways.
How many different bangles are there?
There are two basic types of bangles: a solid cylinder type; and a split, cylindrical spring opening/closing type. The primary distinguishing factor between these is the material used to make the bangles.
How many necklaces can be made with these beads of different Colours?
The correct answer is 2952 .
How many necklaces can be made using 7 beads of which 5 are identical red beads and 2 are identical blue beads?
= 720/(120*2) = 3. So we can have 3 different necklaces.
How many necklaces can be made by using 10 round beads all of a different colors?
There are 10 beads of distinct colours; say, A, B, C, D, E, F, G, H, I and J. If no restriction is imposed then, there are (10!) = 3628800 ways to put these ten distinctly coloured beads into a necklace.
How many necklaces can be formed with 7 beads?
It would be 7! = 5040 diffrent necklaces.
How many arrangements of beads are possible in a bracelet if there are 6 different designs of beads?
Since there are 6! linear arrangements of six distinct beads, the number of distinguishable circular arrangements is 6! 6=5!
How many different way can 4 keys be arranged on a key ring that has no clasp?
Keep one key fixed in any position in the ring. So, the remaining 4 keys can be arranged in 4! = 24 ways.
How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?
5! but correct answer is 21.