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Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

## How many necklaces can you make with 10 beads of colors?

This is easy: count all permutations of 10 beads, 10!, then divide by 20 because we counted each permutation 10 times due to rotation, and counted each of these twice because you can flip the necklace over. Thus the answer is 10!/20 = 181440.

## How many ways can 6 differently Coloured beads be threaded on a string?

Assuming that the beads are different, the first bead can be picked in 6 ways. Then the second bead can be picked in 5 ways. And the third bead can be picked in 4 ways, etc. Multiplying these together, we get 6*5*4*3*2*1 = 720 ways.

## How many ways can 8 beads of different Colour be strung on a ring?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

## How many ways can 6 beads of different colours form a necklace?

When the necklace is unclasped and laid out with its ends separated, there are 6! = 720 distinct ways (permutations) to arrange the 6 different beads.

## How many ways can 10 different beads?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

## How many ways 8 different beads can be arranged to form a necklace?

The number of ways in which 8 different beads be strung on a necklace is. 2500. 2520.

## How many ways can 7 different colored beads be threaded on a string?

It would be 7! = 5040 diffrent necklaces.

## How many arrangements of beads are possible in a bracelet if there are 6 different designs of beads?

Since there are 6! linear arrangements of six distinct beads, the number of distinguishable circular arrangements is 6! 6=5!

## How many ways can 5 keys be put in a ring?

The number of ways of putting 5 different keys in a ring is very similar to that of arranging in a row except. ABCDE and EABCD are the same combinations when placed in a ring. Therefore, The answer is 24.

## How many ways 5 different beads can be arranged to form a necklace?

So, we have to divide 24 by 2. Therefore the total number of different ways of arranging 5 beads is 242=12 .

## How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is 21.

## How many different way can 4 keys be arranged on a key ring that has no clasp?

Keep one key fixed in any position in the ring. So, the remaining 4 keys can be arranged in 4! = 24 ways.